Can you solve the Leonardo da Vinci riddle? - Tanya Khovanova
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Date: 2020-08-22
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Comments and reviews: 6
Babli
I take about 15 minutes to solve the riddle before seeing the answer and explaination and i got correct answer for it whipeeeee
I am 18
( Honestly not a proud moment as the perspective of an 18 years old)
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I take about 15 minutes to solve the riddle before seeing the answer and explaination and i got correct answer for it whipeeeee
I am 18
( Honestly not a proud moment as the perspective of an 18 years old)
reply
perigin3
Is there any proof for the statement that the digits have to add up to match the length of the number. I've found it being said a few times online but can't find any proof of why it's the case
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Is there any proof for the statement that the digits have to add up to match the length of the number. I've found it being said a few times online but can't find any proof of why it's the case
reply
Sam
i solved it by starting everything out as zeros and then putting in the right number in the zero spot and then i kept changing the other numbers to correspond with that until I got the answer.
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i solved it by starting everything out as zeros and then putting in the right number in the zero spot and then i kept changing the other numbers to correspond with that until I got the answer.
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Gwen
The Teded guy: trying different combinations will take forever
Me, guessing a random number of zeroes and getting the number right on the first try: sorry what was that
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The Teded guy: trying different combinations will take forever
Me, guessing a random number of zeroes and getting the number right on the first try: sorry what was that
reply
Deepa
This is one of the only riddles in the 100+ Ted Ed riddles that I, a high schooler could solve. But it's cool this is the 3rd one I solved and so far the easiest.
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This is one of the only riddles in the 100+ Ted Ed riddles that I, a high schooler could solve. But it's cool this is the 3rd one I solved and so far the easiest.
reply
Mirko
So the general solution for n digits will be:
(n-4, 21, 0 (n-7) times, 1000
I have no solution for 5 and 6 tho, anyone got it?
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So the general solution for n digits will be:
(n-4, 21, 0 (n-7) times, 1000
I have no solution for 5 and 6 tho, anyone got it?
reply
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